Question

if x+1/x=8 , find the value of x^2+1/x^2

Answer 1

hope its help you ....
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Answer 2

Answer:

$Value \: of \: x^{2}+\frac{1}{x^{2}}= 62$

Step-by-step explanation:

$Given \:x + \frac{1}{x}= 8\: ---(1)$

\* By algebraic identity:

a² + b² = (a+b)² - 2ab */

$Value \: of \: x^{2}+\frac{1}{x^{2}}\\=\left(x+\frac{1}{x}\right)^{2}-2\times x \times \frac{1}{x}\\=8^{2}-2\\=64 - 2\\= 62$

Therefore,

$Value \: of \: x^{2}+\frac{1}{x^{2}}= 62$

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