Question

if x+1/x =8 , find the value of x2+ 1/x2.​

Answer 1

Answer:

if x+1/x=8

So the value of x2+ 1/x2.

(x+1/x)^2=(8)^2=64

Step-by-step explanation:

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Answer 2

Given :-

$x+\frac{1}{x} = 8$

To find :-

$x^{2} +\frac{1}{x^{2} }$

Process :-

$x+\frac{1}{x} = 8$

Squaring both sides, $(a+b)^{2}=a^{2}+ b^{2}+2ab$

$x^{2} +\frac{1}{x^{2} } +2x\frac{1}{x}$ $=64$

$x^{2} +\frac{1}{x^{2} } +2 = 64$

$x^{2} +\frac{1}{x^{2} } = 62$