if x+1/x ≈9, find tge value of x^2+1/x^2
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Answer:
The answer is 79(approx)
Step-by-step explanation:
Given that : x + 1/x = 9
Squaring both sides
(x+1/x) ² = 81 [U.I. (a+b)²= a²+b²+2ab]
x²+1/x² + 2.x.1/x = 81
x²+1/x²+2 = 81
x²+1/x² = 81-2
x²+1/x² = 79
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