Question

if x+1/x=9, then find the value of x^2+1/x^2
solve as possible guys...​

Answer 1

➲Question

if x+1/x=9, then find the value of x^2+1/x^2

➲Answer

$(x + \frac{1}{x})^{2} = x^{2} + \frac{1}{ {x}^{2} } + 2 \times x \times \frac{1}{x}$

⟹The x are been cancelled.

⟹Then put the 9 at the value of $x + \frac{1}{x}$

$= > (9)^{2} = {x}^{2} + \frac{1}{x ^{2} } + 2 \\ = > {x}^{2} + \frac{1}{x ^{2} } + 2 = (9)^{2}$

$= > {x}^{2} + \frac{1}{ {x}^{2} } = (9 \times 9) - 2 \\ = > {x}^{2} + \frac{1}{ {x}^{2} } = 81 - 2 \\ = > {x}^{2} + \frac{1}{ {x}^{2} } = 79$

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❥Happy learning

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