Question

Pls answer this question attached

Answer 1

Answer:

it is 483

Step-by-step explanation:

because ater adding both no. multiply to 3

Answer 2

Given :   $\boxed {63 ~\triangle~ 7} =12$   here box color is  Red

$\boxed {4 ~\triangle~ 10} =16$    here box color is  Blue

16 Δ 12 = 291  

To Find :  Value of  $\boxed {\boxed {24 ~\triangle~ 16} }$   where outer box is blue and inner box is Red

a, 843

b. 348

C. 483

d. 834​

Solution:

16 Δ 12 = 291  

16 * 12 = 192   reverse 192 to get 291

Hence a Δ b  = reverse of product of a and b

$\boxed {63 ~\triangle~ 7} =12$

63 Δ 7 =  reverse of product of 63 and 7

= reverse of 441  

= 144

$\boxed {144}$  box color is  Red

√144 = 12

Hence red box take square root of the number inside

$\boxed {4 ~\triangle~ 10} =16$  

4 Δ 10 =  reverse of product of 4 and 10

= reverse of 40

=  04

$\boxed {04}$  box color is Blue

4² = 16

Hence Blue box   square  the number inside

Now $\boxed {\boxed {24 ~\triangle~ 16} }$   where outer box is blue and inner box is Red

Blue box and Rd box cancels each other as one is square and other is square root

so left with 24 Δ 16

= reverse of product of 24 and 16

=  reverse of  384

= 483

Hence option C is correct  483

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