if x-1/x=p show that x^3-1/x^3= p^3+3p
Answers
Answer:
Step-by-step explanation:
(x+1)=3x resolves with easiness as: 2x=1=2×.5
x2+1=3x however, we observe this does not atall result same easiness of resolve as 1, and we get to Figure 3 as: (Example1×(x OR 1)) To share that Same Resolve as Figure 1 must also equal 3x(y OR 1) with something more alike 2xy+x=xy+2x=3xy=x2+1 via y=1 onsets that a Factor is thereat via (y or 1)=y=1 has Equality of the Two Options. And we know .5 cannot equal 1, so we know x is not equal 1 nor .5 within status of Parenthetical Shift (See 8 below)
(x−(−1))(x+(−1))=3x=x2−(−1) is the Breakdown of this obvious permutation of Figure 1, which truly would have more easily Formulated: 3x−2=x2−1=(x−1)(x+1) atwhich we know LHS<RHS at x>1 and x<2 LHS<RHS at x<1 we need to thus by Isoscelean Surveyance more approach a Box, as Thus is 3x2−x=x3 is Standing Near enough to recognize the x3 as a Box. And the 3x2−x is Three Imperfect Spheres likely, forensically associable a Former state that: These were 3x2 when inside the x3 Box, but the Contents became Scattered and Spoiled or Peeled.
Thereby those 3 figures, we deduce also the following five:
As of course Parenthetical Shift was Onset by the Middimensional Divisor and also that as is x2 for the Formulation thereof the Force that Onset That Parenthetical Shift is equal B: 3x2−x=x3=[[B3−(1/x)]∙x2=x∙x2 Thereby we know also B3=(x+1)/x Usually Contradicts as: Misnotation Forgetting those brackets involved in 3-(1/x)=x mutating into 3=(x+1)/x, which dissolves at the Hi Order Notation to No longer equal nor include B=1, and Thus onsets necessity for resolve by very inordinary means to derive a Happy Medium of 3B=x+(1/x)=(x+1)/x to figure out what Figure 5 with a Proper value for 3B is, which is not 1=B, contrary to the Author's Belief that these by misappropriating Brackets or Parentheses can requite 3=x+(1/x) without onsetting a New Definition of ‘Parent Thesis’ supplanted the Parentheses, usually caused by: Walking the wrong direction, way too far dure Isoscelean Surveyance of x3=Box.Right atwhich, to see Box.Left, you are likely Stepping on the Box.Right atwhich: It is no longer a Box Anyway but has instead become deformed as indeed Figure 5 Represents.
(3B−(2))3=.53=x3=(3B−(1/x))3 Resolve for B=1 by the Information Provided. In thus we can observe that Indeed there is a Degree of Inquiry to (x3+x)=3x2=3Bx2 that has Substituted 3 for 3B cannot take the form of B=1, Suffice to Suggest that: ‘Parent Thesis’ has Not Supplanted ‘Parentheses’, for we observe B=2.5/3, upon Parenthetical Shift away from 3=(x+1)/x to 3B=x+(1/x)
This does not atall mean Parenthetical Shift within Equations cannot solve, this means: Breaking the parantheses in operations must avoid, so in something extraordinary as is [x+(1/x)]x=x2+1=3x We are Breaking those Parentheses, which is also onsetting: parenthetical shift by inducing B-Factor via xe/xe−1 scaling, forwhich had we used x2+1=3Bx we resolve thereat that x=2 when B=2.5/3, But when we divide by x, to yeild the x+(1/x)=3B we get x=.5 and 2 with the Same Value for B, and (.5 +2)×2 is not 6=3x folks but we do observe that 2+(1/2) =x+(1/x)=.5+(1/.5) is that occurency, and we cannot multiply nor divide by x=2 AND .5 without Squaring Entire to get figure 7.
x2+2+1/x2=32or32B2 In thus, we again get x=2 onsets entire 6.25 = 4+2 +1/4 and x=.5 onsets entire 6.25=.25+2+1/.25 Thus, as We know that x=.5 is Less Metrically Stable, we prefer being paid: 2 Quarters than Torn Dollars is the Logic that Rules x=2, but hereat the suggestion that 2.5=3, is a Misnotation for 2.5 or anything else that cannot prove by the Approach Listed in 8.
When encountering Potential Corruptions due to Parenthetical Shifts, None Should all the much Mind Implanting of B=1 Anywhere, if indeed Bx=x, as those Equations involving Parenthetical Shift do imply by Invoking: B=’Forces involved in Parenthetical Shift’ Bywhich, as we do and can observe if B=1 indeed in Parenthetical Shift or if this was instead just another Case of the Crunched Box, as a Poor Choice for a Stepping Stool to Observe the Far Off Object, the Box formerly equalled, prior to the Crunch and prior to Isoscelean Surveyance.
The significance of B to Parenthetic Shift
Thus, we know Parenthetic Shift truly relies on the equation, asto what does B-Force factually equal, and thus exemplifies best by:
(2a)2=2(a2) , True or False, if True, Explain.
Or
(ax)2B=x(a2) Resolve B relative to a, and x, by the info provided.
Or