If x-1/x= root 5 and x^2+1/x^2 find x+1/x
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If x-1/x= root 5 and x^2+1/x^2 find x+1/x
x - 1/x = √5 ----( 1 )
i ) x² + 1/x² = ( x -1/x)² +2
= (√5)²+2
= 5+2
= 7
ii ) (x+1/x)² = (x-1/x)²+4
=(√5)²+4
= 5+4
=9
Now,
x+1/x = √(x+1/x )²
= √9
= ±3
Therefore ,
x²+1/x² = 7
x+1/x= ±3
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