Question

if x=-1, y=2 and z=1, find the value of x³- z/x+y²+yx/zy​

Answer 1

$\frac{ - 7}{3}$

Step-by-step explanation:

${x}^{3} - \frac{z}{x + {y}^{2} } + \frac{yx}{zy} (x = - 1 \: | \: y = 2 | \: z = 1) \\ = ( { - 1}^{3} - \frac{1}{ - 1 + ( {2}^{2}) } + \frac{2 \times ( - 1)}{1 \times 2} \\ = - 1 - \frac{1}{ - 1 + 4} \: + \frac{ - 2}{2} \\ = - 1 - \frac{1}{3} - 1 \\ = \frac{ - 3 - 1 - 3}{3} \\ = \frac{ - 7}{3}$

Answer 2

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