If x = 1 , y = 2 and z = 5 , find the value of 4x + y + 3z
Answers
Answered by
1
Answer:
= 4(1) + 2 + 3(5)
= 4+2+15
=21
Answered by
1
Answer:
4x+y+3z
=4×1+2+3×5
=4+2+15
=21
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