Question

If x = 1 ,Y = 2 is a solution of the equation
${a}^{2} x + ay = 3$
Then find the value of a

Answer 1

Hii !!


X = 1 and Y = 2





A² X + AY = 3 ----------(1)


Putting the value of X and Y in equation (1) , we get



a² × 1 + a × 2 = 3



a² + 2a = 3


a² + 2a - 3 = 0


a² + 3a - a - 3 = 0


a ( a + 3 ) - 1 ( a + 3 ) = 0.



( a + 3 ) ( a - 1 ) = 0


( a + 3 ) = 0 or ( a - 1 ) = 0


a = -3 or a =1

Answer 2

Hello !!
a² × 1 + a × 2 = 3
a² + 2a = 3
a² + 3a - a - 3 = 0
a( a + 3 )- 1( a + 3 ) = 0.

( a + 3 ) = 0 and( a - 1 ) = 0
a = -3 and a =1