if x=1, y=-2, z=3 find the value of x2+y2+z2-2xy+2yz+2zx
lincolncross05:
i think it is 34 not sure
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if x is 1 and y is -2 and z is 3
Then x2+y2+z2-2xy+2yz+2zx is
(1)2+(-2)2+(3)2-2(1)(-2) +2(-2)(3)+2(3)(1)
2-4+6+4-12+6
18-16 = 2
therefore the value is 2
Then x2+y2+z2-2xy+2yz+2zx is
(1)2+(-2)2+(3)2-2(1)(-2) +2(-2)(3)+2(3)(1)
2-4+6+4-12+6
18-16 = 2
therefore the value is 2
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