Question

if x=1,y=2andz=3find the value of x3+y2+2xyz​

Answer 1

Answer:

If x=1,y=2 and z=3

Then value of x^3+y^2 + 2xyz

(1)^3+(2)^2+2(1)(2)(3)

1+4+12

17

Answer is 17

Answer 2

Answer: The answer is 19.

Step-by-step explanation:

if x=1; y=2; z=3

= x3+y2+2xyz

=(1)3 + (2)2 + 2(1)(2)(3)

=3 + 4 + 2(6)

=3 + 4 + 12

=19