Question

If x=1,y=2is a solution of the equation k2x+ky=3,then find the value of k​

Answer 1

$x = 1 \\ y = 2 \\ 2kx + ky = 3 \\ 2k \times 1 + k \times 2 = 3 \\ 2k + 2k = 3 \\ 4k = 3 \\ k = \frac{3}{4}$

Answer 2

Heya mate here is your answer:

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✍ Since x= 1 and y =2 are the solution then they will satisfy the given equation. Hence we put the values in the equation im place of x and y.

${k}^{2} + 2k - 3 = 0$

${k}^{2} + 3k - 1k - 3 = 0$

$k(k + 3) - 1(k + 3) = 0$

(k-1)=0 and (k+3)=0.

✍So, the values of k are, 1 and -3