Math, asked by aryanadityaaryan617, 2 months ago

IF x\10 -(2x+3)\5 +4=0, what is the value of x? ​

Answers

Answered by aravkataria2009
4

Answer:

\frac{ x  }{ 10  }  - \frac{ -(2x+3)  }{ 5+4  }  =10 \\  = x-\frac{10}{9}\left(-\left(2x+3\right)\right)=100  \\  = x-\frac{10}{9}\left(-2x-3\right)=100  \\  = x-\frac{10}{9}\left(-2\right)x-\frac{10}{9}\left(-3\right)=100  \\  = x+\frac{-10\left(-2\right)}{9}x-\frac{10}{9}\left(-3\right)=100  \\  = x+\frac{20}{9}x-\frac{10}{9}\left(-3\right)=100  \\  = x+\frac{20}{9}x+\frac{-10\left(-3\right)}{9}=100  \\  = x+\frac{20}{9}x+\frac{30}{9}=100  \\  = x+\frac{20}{9}x+\frac{10}{3}=100  \\   = \frac{29}{9}x+\frac{10}{3}=100  \\  = \frac{29}{9}x=100-\frac{10}{3}  \\  = \frac{29}{9}x=\frac{300}{3}-\frac{10}{3}  \\  = \frac{29}{9}x=\frac{300-10}{3}  \\  = \frac{29}{9}x=\frac{290}{3}  \\  = x=\frac{290}{3}\times \left(\frac{9}{29}\right)  \\  = x=\frac{290\times 9}{3\times 29}  \\  = x=\frac{2610}{87}  \\  = x=30

Answered by pranayjamkhandi2009
2

Answer:

34/3

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