Question

IF x\10 -(2x+3)\5 +4=0, what is the value of x? ​

Answer 1

Answer:

$\frac{ x }{ 10 } - \frac{ -(2x+3) }{ 5+4 } =10 \\ = x-\frac{10}{9}\left(-\left(2x+3\right)\right)=100 \\ = x-\frac{10}{9}\left(-2x-3\right)=100 \\ = x-\frac{10}{9}\left(-2\right)x-\frac{10}{9}\left(-3\right)=100 \\ = x+\frac{-10\left(-2\right)}{9}x-\frac{10}{9}\left(-3\right)=100 \\ = x+\frac{20}{9}x-\frac{10}{9}\left(-3\right)=100 \\ = x+\frac{20}{9}x+\frac{-10\left(-3\right)}{9}=100 \\ = x+\frac{20}{9}x+\frac{30}{9}=100 \\ = x+\frac{20}{9}x+\frac{10}{3}=100 \\ = \frac{29}{9}x+\frac{10}{3}=100 \\ = \frac{29}{9}x=100-\frac{10}{3} \\ = \frac{29}{9}x=\frac{300}{3}-\frac{10}{3} \\ = \frac{29}{9}x=\frac{300-10}{3} \\ = \frac{29}{9}x=\frac{290}{3} \\ = x=\frac{290}{3}\times \left(\frac{9}{29}\right) \\ = x=\frac{290\times 9}{3\times 29} \\ = x=\frac{2610}{87} \\ = x=30$

Answer 2

Answer:

34/3

Step-by-step explanation:

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