Question

If x=10 is one root of the quadratic equation x²-2kx-6=0 then find value ok k.​

Answer 1

Step-by-step explanation:

Let

p(x) = x²-2kx-6=0

x= 10 is one root of the quadratic equation

Remainder = p(10) = 0

=> p(10)=0

=> (10)²-2k(10) - 6 = 0

=> 100-20k-6=0

=> -20k=6-100

=> - 20k = -94

=> k=94/20

=> k=47/10

Answer 2

Answer:k=4.7

Step-by-step explanation:x=10 root means f(10)=0

By solving this u cand find k