if x+11y=7 and xy=2, find the value if x2 find the value of x2+121y2
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Hi here to help you
As given that x+11y=7
Square on both sides,
(x+11y)²=7²
x²+121y²+2(11xy) =49
Putting the given values
x²+121y²+(2*11*2)=49
x²+121y²+44=49
x²+121y²=49-44
x²+121y²=5
I hope this will help you
As given that x+11y=7
Square on both sides,
(x+11y)²=7²
x²+121y²+2(11xy) =49
Putting the given values
x²+121y²+(2*11*2)=49
x²+121y²+44=49
x²+121y²=49-44
x²+121y²=5
I hope this will help you
abhi569:
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