if x+11y=7and xy=2,find the value of x^2+121y^2
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5
Answer:
5
Step-by-step explanation:
(a + b)²=a²+ b² + 2ab
( x + 11y)² = x² + 121y² + 22xy
7² = x² + 121y² + 22 × 2
49 - 44 = x² + 121y²
= 5
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