Math, asked by apsundar14, 2 days ago

IF X=√13+1
FIND X². find it please​

Answers

Answered by isha4291
1

Answer:

m- (m-1)/2 =1-(m-2)/3

Step-by-step explanation:

m- (m-1)/2 =1-(m-2)/3

Answered by HridayPawar
1

Answer:

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Step-by-step explanation:

x+1/x=(13)^1/2. Now the value of

x-1/x=[(x+1/x)^2-4]^1/2

=(13-4)^1/2=(9)^1/2

or,x-1/x=3

Again, x^4-1/x^4=(x^2+1/x^2)(x+1/x)(x-1/x)=[(x+1/x)^2-2)]×(13)^1/2×3=(13-2)×3(13)^1/2

or,x^4-1/x^4=33(13)^1/2. Now to find the value of x^5-1/x^5 we should proceed as under: (x^4-1/x^4)×(x+1/x)=x^5-1/x^3+x^3-1/x^5=x^5-1/x^5+(x^3-1/x^3)

or, x^5-1/x^5

=(x^4-1/x^4)(x+1/x)—(x^3-1/x^3)

=33×(13)^1/2×(13)^1/2–(x-1/x)(x^2+1/x^2+1).

=33×13-3(13-2+1)

=429-3×12=429–36

=393

So,x^5-1/x^5=393

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