If x,13,y,3are in ap find x and y
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X,13,y,3 are in AP
using arithmetic mean
y=13+3/2
y=16/2
y=8
a2-a1=a3-a2
13-x=8-13
13-x= -5
-x= -5-13
-x= -18
X=18
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Answer:
x=18 and y=8
Step-by-step explanation:
a1=x, a2=13, a3=y and a4=3
If x,13,y,3are in ap
Then, a2-a1=a4-a3 and a2-a1=a3-a2
a2-a1=a4-a3
13-x=3-y
x-y=13-3
x-y=10 ......(i)
and
a2-a1=a3-a2
13-x=y-13
x+y=26 .......(ii)
Adding equation (i) and (ii) we get
2x=36
x=18
Substituting the value of x in equation (ii), we get
18+y=26
y=26-18
y=8
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