If x= 14√2 find the value of (x-1/x)³
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\begin{gathered}x { }^{2} + 11x { }^{2} = 14 \ \\ (x + 1x {}^{2} ) - 2.x.1 x14 \\ take square root sides \\(x + 1x ) = 4 \\ then \\ x {}^{3} + 1x {}^{3} - 3.x.1x(x + 1x) \\ (x + 1x) {}^{3} - 3(x + 1x) \\ (4) {}^{3} - 3(4) \\ 64 - 12 \\ \\ 52 \: answer\end{gathered}
x
2
+11x
2
=14
(x+1x
2
)−2.x.1x14
takesquarerootsides
(x+1x)=4
then
x
3
+1x
3
−3.x.1x(x+1x)
(x+1x)
3
−3(x+1x)
(4)
3
−3(4)
64−12
52answer
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