Question

If x=16 is one root of quadratic equation X2-2 (7x+16)=0 ,,,,,,,, find the other root

Answer 1

${x}^{2} - 2(7x + 16) = 0 \\ {x}^{2} - 14x - 32 = 0 \\ {x}^{2} - 16x + 2x - 32 = 0 \\ x(x - 16) + 2(x - 16) = 0 \\ (x + 2)(x - 16) = 0 \\ x = 16 \\ x = - 2$
we already know that 16 is it's root and now we get to know that value of x is also -2.