Question

If X

2 +

1

2

= 34, find the value of X +

1



and X

3 +

1

3

using only the positive value of

X +

1

​

Answer 1

Answer:

Please mark BRAINLIEST

Answer 2

Answer:

${x}^{2} + \frac{1}{ {x}^{2} } = 34 \\ adding \: 2 \: on \: both \: sides \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = 34 + 2 \\ {(x + \frac{1}{x} )}^{2} = {6}^{2} \\ x + \frac{1}{x} = 6 \\ cubing \: on \: both \: sides \\ {(x + \frac{1}{x} )}^{3} = {6}^{3} \\ {x}^{3} + \frac{1}{ {x}^{3} } + 3 \times x \times \frac{1}{x} (x + \frac{1}{x} ) = 216 \\ {x}^{3} + \frac{1}{ {x}^{3} } + 3 \times 6 = 216 \\ {x}^{3} + \frac{1}{ {x}^{3} } = 216 - 18 = 198$