If x^2+1/4x^2=17. Find the value of x-1/2x
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4
x²+1/4x²=17,
x²+1/(2x)²=17,
x²+1/(2x)²-2+2=17,
[x+1/(2x)]²=17-2,
[x+1/(2x)]²=15,
then
(x-1/2x)=√15
x²+1/(2x)²=17,
x²+1/(2x)²-2+2=17,
[x+1/(2x)]²=17-2,
[x+1/(2x)]²=15,
then
(x-1/2x)=√15
RukhsarParvin:
x^2+1/(2x)^2+2-2=17
how it will come
x^2+1/(2x)^2+2-2=17
we can cut the 2
Thank you
Answered by
4
x²+1/4x²=17,
x²+1/(2x)²=17,
x²+1/(2x)²-2+2=17,
[x+1/(2x)]²=17-2,
[x+1/(2x)]²=15,
then
(x-1/2x)=√15
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