if x^2+1/9x^2=25/36 find x^3+1/27x^3
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x3+127x3=±91216
Explanation:
Here's an alternative method that does not require calculating x:
Note that:
(x+13x)2=x2+23+19x2=2536+23=4936=(76)2
So:
(x+13x)=±76
Then:
±343216=(x+13x)3
±343216=x3+x+13x+127x3
±343216=x3+127x3±76
So:
x3+127x3=±(343216−76)=±(343216−252216)=±91216
Explanation:
Here's an alternative method that does not require calculating x:
Note that:
(x+13x)2=x2+23+19x2=2536+23=4936=(76)2
So:
(x+13x)=±76
Then:
±343216=(x+13x)3
±343216=x3+x+13x+127x3
±343216=x3+127x3±76
So:
x3+127x3=±(343216−76)=±(343216−252216)=±91216
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