plezzz answer it is emergency
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Hola there,
=> 3x² - 2√6x + 2 = 0
=> 3x² -√6x - √6x + 2 = 0
=> √3x(√3x - √2) - √2(√3x - √2) = 0
=> (√3x - √2)(√3x - √2) = 0
=> (√3x - √2)² = 0
=> x = √2/√3 and √2/√3
Hope this helps...:)
=> 3x² - 2√6x + 2 = 0
=> 3x² -√6x - √6x + 2 = 0
=> √3x(√3x - √2) - √2(√3x - √2) = 0
=> (√3x - √2)(√3x - √2) = 0
=> (√3x - √2)² = 0
=> x = √2/√3 and √2/√3
Hope this helps...:)
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2
I hope it will helps u...
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