Math, asked by singhakshat554, 12 days ago

If x = √2 + 1 , find the value of (x - 1/x)² .

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Answered by Anonymous
2

4

Step-by-step explanation:

(x -  \frac{1}{x} )^{2}

( \sqrt{2}  + 1 -  \frac{1}{ \sqrt{2} + 1 } )^{2}

( \sqrt{2}  + 1 -  \frac{1}{ \sqrt{2} + 1 } \times  \frac{ \sqrt{2} - 1 }{ \sqrt{2} - 1 }  )^{2}

( \sqrt{2}  + 1 -  \frac{ \sqrt{2} - 1 }{ ( { \sqrt{2} )}^{2} -  {1}^{2}   }  )^{2}

( \sqrt{2}  + 1 -  \frac{ \sqrt{2} - 1 }{ { {2} } -  {1}   }  )^{2}

(√2 + 1 - (√2 -1))²

(√2 + 1 - √2 + 1)²

(2)²

= 4

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