If x=√2+1,find the value of x²+1/x²
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x = √2 + 1
TO Find VALUE OF X^2 + 1/X^2
Let x = √2 + 1
therefore,
1/x = 1/√2 + 1
rationalise the value of 1/x
we get,
1/√2 + 1 X √2 - 1 / √2 - 1
√2 - 1 / 2 - 1
√2 - 1 = 1/x
x^2 + 1/x^2
it is in the form of = a^2 + b^2
=> (a + b)^2 - 2ab
(x^2 + 1/x^2 )
(x + 1/x )^2 - 2x*1/x
(√2 + 1 + √2 - 1 )^2 - 2
(2√2 )^2 - 2
8 - 2 = 6 = ANSWER
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