Question

if (x^2-1)is a factor of ax^4 +bx^3+cx^2+dx+e,show that a+c+e=b+d=0

Answer 1

Hey Friend ☺

Since ( x^2 - 1 ) is a factor of ax^4 + bx^3 + cx^2 + dx + e

Zero of ( x^2 - 1 )

x^2 = 1

x = 1.

Using factors theorem

So p ( 1 ) = 0

P ( 1 ) = ax^4 + bx^3 + cx^2 + dx + e

》0 = a ( 1 )^4 + b ( 1 )^3 + c ( 1 )^2 + d ( x ) + e

》0 = a + b + c + d + e.

Hence proved

Hope it helps you ..!!

✌

Answer 2

Hope it wl b helpful....