Math, asked by priyanka95, 1 year ago

If (x^2-1) is a factor of px^4+qx^3+rx^2+sx+t, show that p+r+t=q+s=0

Answers

Answered by chiefLucky
6
x^2-1=0
x^2=1
x=1
f(1)=p(1)^4+q(1)^3+r(1)^2+s(1)+t=0
||p+q+r+s+t=0
HENCE PROVEN.
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priyanka95: Thanks
chiefLucky: No prob
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