Question

If x^2+1_x^2=14,then evaluate x^3+1_x^3​

Answer 1

Answer:

x+1/x = 14

(x+1/x)* -2.x.1/x = 14

X+1/x) -2 = 14

(x+1/x ) = 16

take square root both sides

x+1/x) = 4

then,

x+1/x3 = (x+ 1/x) -3.x.1/x(x +1/x)

= (x +1/)* -3x + 1/)

(4-3(4)

= 64 12

52

Step-by-step explanation:

Plz mark as brainlist

Answer 2

Step-by-step explanation:

x ^ 2 + 1 / (x ^ 2) = 14

(x+1/x)^ 2 -2.x.1/x=14

(x + 1 / x) ^ 2 - 2 = 14

(x + 1 / x) ^ 2 = 16

take square root both sides

(x + 1 / x) = 4

then,

x^ 3 +1/x^ 3 =(x+1/x)^ 3 -3.x.1/x(x+1/x)

=(x+1/x)^ 3 -3(x+1/x)

=(4)^ 3 -3(4)

=64-12

=52