if x^2 + 1/x^2=7 find 1) x-1/x , 2) x+1/x , 3) 3x^2 -3/x^2
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Step-by-step explanation:
x^2+(1/x^2)=7
x-(1/x)=??
square x-(1/x)
x^2-2+(1/x^2)
substitute
x^2+(1/x^2)=7
7-2=5
(x-[1/x])^2=5
take the square root of both sides
x-(1/x)=√5
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solution starts from left side !
hopefully its helped u :)
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