If x^2+1/x^2=7 then x^3+1/x^3=?
Answers
Answered by
3
Hey!!!....Here is ur answer
x^2+1/x^2=7
x^2+1/x^2+2=9
x+1/x=3
x^3+1/x^3+3×3=27
x^3+1/x^3=18
Hope it will help you
x^2+1/x^2=7
x^2+1/x^2+2=9
x+1/x=3
x^3+1/x^3+3×3=27
x^3+1/x^3=18
Hope it will help you
Answered by
4
Heya ✋
Let see your answer !!!!
Given that
x^2 + 1/x^2 = 7
x^3 + 1/x^3 = ?
Solution
x^2 + 1/x^2 = 7
=> x^2 + 1/x^2 + 2 = 9
=> (x + 1/x)^2 = 9
=> x + 1/x = √9
=> x + 1/x = 3
Hence ,
x^3 + 1/x^3
= (x + 1/x) (x^2 - x × 1/x + 1/x^2)
= 3 (x^2 - 1 + 1/x^2)
= 3 (x^2 + 1/x^2 - 1)
= 3 (7 - 1)
= 3 × 6
= 18
Thanks :)))))
Let see your answer !!!!
Given that
x^2 + 1/x^2 = 7
x^3 + 1/x^3 = ?
Solution
x^2 + 1/x^2 = 7
=> x^2 + 1/x^2 + 2 = 9
=> (x + 1/x)^2 = 9
=> x + 1/x = √9
=> x + 1/x = 3
Hence ,
x^3 + 1/x^3
= (x + 1/x) (x^2 - x × 1/x + 1/x^2)
= 3 (x^2 - 1 + 1/x^2)
= 3 (x^2 + 1/x^2 - 1)
= 3 (7 - 1)
= 3 × 6
= 18
Thanks :)))))
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