CHAPTER → INEQUALITY
Q. 2x-3/3x-7 > 0
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Given Equation is : (2x - 3)/(3x - 7) > 0
Consider the Numerator :
(i)
= > 2x - 3 = 0
= > 2x = 3
= > x = 3/2.
(ii)
= > 2x - 3 < 0
= > 2x < 3
= > x < 3/2
(iii)
= > 2x - 3 > 0
= > 2x > 3
= > x > 3/2.
Now, Consider the denominator:
(i)
= > 3x - 7 = 0
= > 3x = 7
= > x = 7/3
(ii)
= > 3x - 7 < 0
= > 3x < 7
= > x < 7/3.
(iii)
= > 3x - 7 > 0
= > 3x > 7
= > x > 7/3.
As u can see the ranges x < 3/2 or x > 7/3 satisfy the condition(> 0).
Hope this helps!
Consider the Numerator :
(i)
= > 2x - 3 = 0
= > 2x = 3
= > x = 3/2.
(ii)
= > 2x - 3 < 0
= > 2x < 3
= > x < 3/2
(iii)
= > 2x - 3 > 0
= > 2x > 3
= > x > 3/2.
Now, Consider the denominator:
(i)
= > 3x - 7 = 0
= > 3x = 7
= > x = 7/3
(ii)
= > 3x - 7 < 0
= > 3x < 7
= > x < 7/3.
(iii)
= > 3x - 7 > 0
= > 3x > 7
= > x > 7/3.
As u can see the ranges x < 3/2 or x > 7/3 satisfy the condition(> 0).
Hope this helps!
siddhartharao77:
:-)
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