if x+2 , 2x+3 are in AP find x
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Given,
x+2,2x,2x+3 are in A.P.
⇒(2x)−(x+2)=(2x+3)−(2x)
2x−x−2=2x+3−2x
x−2=3
∴x=5
The consecutive numbers are : 5+2,2(5),2(5)+3
⇒7,10,13
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