Question

If x+2,2x+5,4x+8 are in ap the find value of x

Answer 1

$\textbf{Given:}$

$\text{x+2, 2x+5 and 4x+8 are in A.P}$

$\textbf{To find:}$

$\text{The value of x}$

$\textbf{Solution:}$

$\text{We know that, a,b and c are in A.P, then b=\dfrac{a+c}{2} }$

$\text{Since x+2, 2x+5 and 4x+8 are in A.P, we have}$

$2x+5=\dfrac{x+2+4x+8}{2}$

$2x+5=\dfrac{5x+10}{2}$

$4x+10=5x+10$

$\implies\bf\,x=0$

$\therefore\textbf{The value of x is 0}$

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