Question

If x = [(2/3)^2]^3*[1/3]^-2*3^-1*1/6.Find the reciprocal​

Answer 1

Answer:

With the given equation, XX should be a 2×22×2 matrix.

Let X=[acbd]X=[abcd]

Then, [acbd][142536]=[−72−84−96][abcd][123456]=[-7-8-9246]

⇒[a+4bc+4d2a+5b2c+5d3a+6b3c+6d]=[−72−84−96]⇒[a+4b2a+5b3a+6bc+4d2c+5d3c+6d]=[-7-8-9246]

∴a+4b=−7→(1)∴a+4b=-7→(1)

2a+5b=−8→(2)2a+5b=-8→(2)

3a+6b=−9⇒a+2b=−3→(3)3a+6b=-9⇒a+2b=-3→(3)

c+4d=2→(4)c+4d=2→(4)