If x=2/3 and 2
and b.
LEVEL-2
--3 are the roots of the equation ax2 + 7x + b = 0, find the values of a
[CBSE 2016]
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Answer:
ax^2 + 7x + b
It is given that roots of the equation are x = 2/3 and b = -3
Therefore, a(2/3)^2 + 7(2/3) + (-3) = 0
4a/9 + 14/3 - 3 = 0
4a/9 + 14/3 - 9/3 = 0
4a/9 + 5/3 = 0
4a/9 = -5/3
4a = (-5×9)/3
4a = -45/3
4a = -15
a = -15/4
a = -3.75
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