If x = 2 – √3, find the value of (x -1/x)cube
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Answer: -24√3
Step-by-step explanation:
x = 2 - √3 __(1)
Thus, 1/x = 1/(2 - √3)
Rationalising the denominator,
= (2 + √3) / [(2 - √3)(2 + √3)]
= (2 + √3) / [2² - (√3 )²]
= (2 + √3) / (4 - 3)
= 2 + √3 __(2)
Now, Subtracting eq. (1) and (2)
x - 1/x = 2 - √3 - (2 + √3)
= 2 - √3 - 2 - √3
x - 1/x = -2√3
Thus, Cubing both the sides:
(x - 1/x)³ = (- 2√3)³
(x - 1/x)³ = -24√3
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