If x=2+√3,find the value of x^3+1/x^3
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X = 2 + √3
1/x = 1/(2 + √3)
= (2 -√3)/(2 +√3)(2 -√3)
= (2 -√3)/(2² -√3²)
= (2 - √3)
hence, x + 1/x = (2+√3)+(2-√3) = 4
x³ + 1/x³ = (x + 1/x)³ -3(x + 1/x)
= (4)³ - 3(4)
= 64 -12
= 52
this is your answer...
1/x = 1/(2 + √3)
= (2 -√3)/(2 +√3)(2 -√3)
= (2 -√3)/(2² -√3²)
= (2 - √3)
hence, x + 1/x = (2+√3)+(2-√3) = 4
x³ + 1/x³ = (x + 1/x)³ -3(x + 1/x)
= (4)³ - 3(4)
= 64 -12
= 52
this is your answer...
VinayakP1:
in which std you are
ok i am in 9th
thanks bye
wlcm?
okk bye
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