if x= 2+√3 , find x^2 + 1/ x ^2
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Given :-x=2+√3
x^2+1/x^2 =(2+√3)^2+1/(2+√3)^2 =(2)^2+2*2*√3+(√3)^2+1/(2)^2+2*2*√3+(√3)^ =4+4√3+3+1/4+4√3+3 =4+4√3+4/4+4√3+3 =4(1+√3+1)/4(1+√3)+1 =2+√3/1+√3+1 =2+√3/2+√3 =1(which is the required answer) [If this answer helped you then please mark me as brainliest ]
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