If x=2/3 is a solution of the quadratic equation 7x^2+mx-3=0; find the value of m.
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x=2/3
=>7(2/3)^2+m(2/3)-3=0
=>7(2/3*2/3)+2/3m-3=0
=>28/9+2/3m-3=0(TAKING 9 AS THE LCM)
=>28+6m-9/9=0
=>28+6m-9=0(TAKING THE DEN0MINATOR FORM LHS TO RHS)
=>19+6m=0
=>6m=0-19
=>6m=-19
=>m= -19/6
I HOPE THAT IT HELPS YOU
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