Question

if x=2-√3 , then the value of x^2+1/x^2 and x^2-1/x^2 ?

Answer 1

taking square both sides
${x }^{2} = (2 - \sqrt{3) {}^{2} }$
x2=4-3
x2=1

=x2+1/x2
=1+1/1=1+1/1=2/1=2

=x2-1/x2
=1-1/1=1-1/1=0/1=0