Question

If x=2/3,x=-3 are roots of ax² + 7x+b=0
3
Find a, b.​

Answer 1

The given equation is ax² + 7x+b=0

Its root are given as x1=2/3,x2=-3

x1+x2=-b/a

2/3-3=-7/a

2-9/3=-7/a

-7/3=-7/a

a=3

Also

x1×x2=b/a

2/3×-3=b/a

-2=b/3

b=-6

thus the value of a and b are 3 and-6 respectively