Math, asked by jahnabidutta659, 22 days ago

if x=(-2/3),y=3/4 and z=(-4/5),
evaluate
(i) xy+yz+xz (ii) (x+y+z)*xyz​

Answers

Answered by vitex1504
1

Answer:

Answer is xy+yz+xz.

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Answered by BredGorl
1

Answer:

(i) -17/30

(ii) -43/150

Step-by-step explanation:

Given: x=(-2/3), y=3/4 and z=(-4/5)

(i) xy+yz+xz

= (-2/3)(3/4) + (3/4)(-4/5) + (-4/5)(-2/3)

= (-2/4) + (-3/5) + (8/15)

= -1/2 - 3/5 + 8/15

Taking LCM,

= -15-18+16/30

= -17/30

(ii) (x+y+z)*xyz

= [(-2/3) + (3/4) + (-4/5)] × [(-2/3) × (3/4) × (-4/5)]

= (-40+45-48/60) × (2/5)

= -43/60 × 2/5

= -43/150

Hope it helps!!

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