Math, asked by kartik0508, 1 year ago

If x^2-3x +3=0, find (x-1)^16+ 1/(x-1)^16​

Answers

Answered by spiderman2019
1

Answer:

65536.00001525879.

Step-by-step explanation:

x² - 3x + 3 = 0

(x-1)(x-3) = 0

x = 1 or 3.

when x = 1,

(x-1)¹⁶ + 1/(x-1)¹⁶ = 0 + 1/0 is invalid

when x = 3,

(3-1)¹⁶ + 1/(3-1)¹⁶ = 2¹⁶ + 1/2¹⁶ = 65536.00001525879.

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