If x^2 - 4/x^2 =3,then x =
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x² - 4/x² = 3
multiply both sides by x²
x⁴ - 4 = 3x²
x⁴ - 3x² - 4 = 0
=> x⁴ - 4x² + x² - 4 = 0
=> x² ( x² - 4) + 1 (x² - 4) = 0
=> (x² + 1)(x² - 4) = 0
=> x² + 1 = 0 and x² - 4 = 0
=> x² = -1 and x = ± 2
=> x = ±√-1 which is imaginary
=> x = + i, x = - i x = - 2 and x = +2
therefore real values of x are - 2 and +2
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