Question

If x^-2=64 ,then x^1/3+x^0=

Answer 1

x^-2=64

which gives

1/x^2=64

x^2=1/64

x=√1/64

x=1/8

now, x^1/3+x^0  (x^1=x and x^0=1 (anything raised to power zero is one))

now, x=1/8 as found above

x/(3+1)

x/4

1/(4*8)

1/32 is your answer

hope this helps and u understand well :)