Question

if x=2^8 and x^x=2^y then find the value of y​

Answer 1

${x}^{x} = ({{2}^{8}})^{{2}^{8}} = {2}^{y} = {2}^{8 \times {2}^{8}} = {2}^{ {2}^{3} \times {2}^{8} } = {2}^{ { {2}^{11}} }$

y = 2^11

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