If X=2 & X=0 are the root of the polynomial f(x)= 2x3-5x2+ax+b.find a & b
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Hey mate thank for the question
Hope it helps
X=0,X=2
first putting x=2
By reminder theorem f(2)=0
0=2x3-5x2+ax+b
0=2*(2)3-5*(2)2+a*2+b
0=2*8-5*4+2a+b
0=16-20+2a+b
0=-4+2a+b
2a+b=4-----------(1)
second putting x=0
by reminder theorem f(x)=0
0=2*(0)3-5(0)2+a*0+b
0=0+b
b=0
putting the value of b in eq (1)
2a+b=4
2a+0=4
2a=4
a=4/2
a=2
Hope it helps
X=0,X=2
first putting x=2
By reminder theorem f(2)=0
0=2x3-5x2+ax+b
0=2*(2)3-5*(2)2+a*2+b
0=2*8-5*4+2a+b
0=16-20+2a+b
0=-4+2a+b
2a+b=4-----------(1)
second putting x=0
by reminder theorem f(x)=0
0=2*(0)3-5(0)2+a*0+b
0=0+b
b=0
putting the value of b in eq (1)
2a+b=4
2a+0=4
2a=4
a=4/2
a=2
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