Question

If (x-2)and(x-1/2)are the factors of px2+5x+r then show p=r

Answer 1

Given :

( X - 2 ) and ( X - 1/2 ) are The factors of px square + 5 X + r

Procedure :

X - 2 = 0

X = 2

P ( 2 ) square + 5 ( 2 ) + r

P ( 4 ) + 10 + r

4p + 10 + r ................. eq . 1

X - 1/2 = 0

X = 1/2

p ( 1/2 ) square + 5 ( 1 /2 ) + r

p ( 1/4 ) + 5/ 2 + r

1/4 p + 5/2 + r ................. eq . 2

From eq.1 and eq.2

4p + 10 + r + ¼ p + 5/2 + r = 0